Which number is mystery?

A mystery number is a number that can be expressed as the sum of two numbers and those two numbers should be the reverse of each other.

geeksforgeeks.org - Check if a number is a Mystery Number - GeeksforGeeks

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Given a number, check whether it is a mystery number or not. A mystery number is a number that can be expressed as the sum of two numbers and those two numbers should be the reverse of each other.

Examples:

Input : n = 121

Output : 29 92 Input : n = 22

Output : 11 11

The idea is to try every possible pair smaller than or equal to n.

Below is the implementation of the above approach.

C++

#include using namespace std; int reverseNum( int x) { string s = to_string(x); reverse(s.begin(), s.end()); stringstream ss(s); int rev = 0; ss >> rev; return rev; } bool isMysteryNumber( int n) { for ( int i=1; i <= n/2; i++) { int j = reverseNum(i); if (i + j == n) { cout << i << " " << j; return true ; } } cout << "Not a Mystery Number" ; return false ; } int main() { int n = 121; isMysteryNumber(n); return 0; } Java class GFG { static int reverseNum( int x) { String s = Integer.toString(x); String str= "" ; for ( int i=s.length()- 1 ;i>= 0 ;i--) { str=str+s.charAt(i); } int rev=Integer.parseInt(str); return rev; } static boolean isMysteryNumber( int n) { for ( int i= 1 ; i <= n/ 2 ; i++) { int j = reverseNum(i); if (i + j == n) { System.out.println( i + " " + j); return true ; } } System.out.println( "Not a Mystery Number" ); return false ; } public static void main(String []args) { int n = 121 ; isMysteryNumber(n); } } Python3 def reverseNum(x): s = str (x) s = s[:: - 1 ] return int (s) def isMysteryNumber(n): for i in range ( 1 , n / / 2 + 1 ): j = reverseNum(i) if i + j = = n: print (i, j) return True print ( "Not a Mystery Number" ) return False n = 121 isMysteryNumber(n) C# using System; class GFG { static int reverseNum( int x) { string s = x.ToString(); string str= "" ; for ( int i=s.Length-1;i>=0;i--) { str=str+s[i]; } int rev=Int32.Parse(str); return rev; } static bool isMysteryNumber( int n) { for ( int i=1; i <= n/2; i++) { int j = reverseNum(i); if (i + j == n) { Console.WriteLine( i + " " + j); return true ; } } Console.WriteLine( "Not a Mystery Number" ); return false ; } public static void Main() { int n = 121; isMysteryNumber(n); } } PHP

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Javascript

Output: 29 92

Time Complexity: O(n)

Auxiliary Space: O(log 10 n)

geeksforgeeks.org - Check if a number is a Mystery Number - GeeksforGeeks

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